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The height y (in feet) of a ball thrown by a child is
y= -1/14 x^2+6x+3

The height y (in feet) of a ball thrown by a child is y= -1/14 x^2+6x+3-example-1
User Niksvp
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Answer:

We can analyze this equation to determine information about the trajectory of the ball.

The equation of the ball's height is given by:

y = -1/14 x^2 + 6x + 3

where y is the height of the ball (in feet) and x is the time (in seconds).

The equation is in the form of a quadratic function, which means that the height of the ball will follow a parabolic path.

The coefficient of x^2 is negative (-1/14), which means that the graph of the function will open downwards, indicating that the ball will reach a maximum height and then fall back down.

The maximum height occurs at the vertex of the parabolic function, which can be found using the formula:

x = -b/2a

where a is the coefficient of x^2 and b is the coefficient of x. In this case, a = -1/14 and b = 6, so:

x = -6 / 2(-1/14) = 42

Therefore, the ball will reach its maximum height at 42/2 = 21 seconds.

Substituting x = 21 into the equation, we can find the maximum height:

y = -1/14 (21^2) + 6(21) + 3 = 120 feet

Therefore, the ball will reach a maximum height of 120 feet after 21 seconds, and then fall back down, following the same parabolic path.

Explanation:

User Uday Pratap Singh
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