Answer:
32D
Explanation:
To find the value of 10(c+3) + 6(c-5) in terms of D when c = 2D, you can substitute the value of c into the expression:
10 ( 2 D + 3 ) + 6 ( 2D - 5 )
Now, distribute the numbers outside the parentheses:
20D + 30 + 12D - 30
Combine like terms:
( 20D + 12D ) + ( 30 - 30 )
This simplifies to:
32D + 0
32D