Question

Find the zeros of each function by using a graph and a table. f(x)=x^2+2x–24.

Answer 1

Step-by-step explanation

Step 1

`f(x)=x^2+2x-24`

Zeros

A(-6,0) B(4,0)

because

`\begin{gathered} f(x)=x^2+2x-24 \\ f(-6)=(-6)^2+2(-6)-24=36-12-24=0 \\ f(4)=4^2+2\cdot4-24=16+8-24=0 \end{gathered}`

Step 2

table

`\begin{gathered} (-6,0) \\ (4,0) \\ f(-1)=-1^2+2\cdot-1-24=1-2-24=-25 \\ (1,-25) \\ \end{gathered}`

I hope this helps you