Question

julieta and her children went into a grocery store where they sell bananas for $0.40 each and mangos for $1 each. Julieta has $9.80 to spend and must buy no less than 11 bananas and mangos all together. if Julieta decided to buy 9 bananas, determine all possible values for the number of mangos that she could buy

Answer 1

After buying 9 bananas, Julieta can spend the remaining $6.20 on mangos. With mangos priced at $1 each, she could buy between 2 to 6 mangos to meet the minimum requirement of 11 fruits in total.

Step-by-step explanation:

Julieta decided to buy 9 bananas at $0.40 each, so first we need to calculate the total cost of the bananas. 9 bananas × $0.40 per banana = $3.60 on bananas. Since Julieta has a total of $9.80 to spend, we subtract the cost of the bananas from her total budget to find out how much money is left for mangos. $9.80 - $3.60 = $6.20 remaining for mangos.

Since mangos cost $1 each, the maximum number of mangos Julieta can buy with the remaining money is calculated by dividing the remaining budget by the price per mango. $6.20 ÷ $1 per mango = 6 mangos. Considering Julieta must buy at least 11 pieces of fruit in total, and she has already chosen 9 bananas, she could buy 2 more pieces of fruit at minimum. Therefore, the range of possible mangos she can buy is 2 to 6 mangos.

Answer 2

Answer: Julieta must buy at least 2 mangos when she buys 9 bananas. Therefore, the possible values for the number of mangos she could buy are 2 or any whole number greater than 2, depending on her budget and preferences.

Explanation: Using the information given to find the possible values for the number of mangos that Julieta can buy when she decides to buy 9 bananas. First, we know that Julieta has $9.80 to spend. She spends $0.40 on each banana and $1 on each mango. So, let's set up an equation to represent the cost of buying 9 bananas and some number of mangos (let's call it 'm'):

Cost = (Number of Bananas * Cost per Banana) + (Number of Mangos * Cost per Mango)

Cost = (9 * $0.40) + (m * $1)

Cost = $3.60 + $m

Now, we need to ensure that Julieta spends no more than her $9.80 budget, and she must buy no less than 11 bananas and mangos combined. So we have two conditions:

1. Cost ≤ $9.80

2. Number of Bananas (9) + Number of Mangos (m) ≥ 11

Now let's consider the budget constraint:

Cost ≤ $9.80

$3.60 + $m ≤ $9.80

Subtract $3.60 from both sides of the inequality:

$m ≤ $9.80 - $3.60

$m ≤ $6.20

So, Julieta can spend up to $6.20 on mangos when she buys 9 bananas.

Now, consider the constraint on the total number of items:

Number of Bananas (9) + Number of Mangos (m) ≥ 11

9 + m ≥ 11

Subtract 9 from both sides of the inequality:

m ≥ 11 - 9

m ≥ 2

So again Julieta must buy at least 2 mangos when she buys 9 bananas. Therefore, the possible values for the number of mangos she could buy are 2 or any whole number greater than 2, depending on her budget and preferences.