The osmotic pressure difference between sea water and fresh water is 29.3 atm
How to calculate the osmotic pressure difference?
First, we shall calculate the mole of the salt (i.e NaCl) in the fresh water. Details below:
- Mass of NaCl = 35 g
- Molar mass of NaCl = 58.5 g/mol
- Mole of NaCl =?
Mole of NaCl = Mass of NaCl / Molar mass of NaCl
= 35 / 58.5
= 0.598 mole
Next, we shall obtain the molarity of the salt. Details below:
- Mole of NaCl = 0.598 mole
- Mass of water = 1 kg = 1000 g
- Volume of water = Mass of water = 1000 = 1000 mL = 1 L
- Molarity of salt =?
Molarity of salt = mole / volume
= 0.598 / 1
0.598 M
Finally, we shall calculate the osmotic pressure. This is shown below:
- Molarity of salt (M) = 0.596 M
- Van't Hoff factor for salt, NaCl (i) = 2 (since NaCl is an ionic compound)
- Gas constant (R) = 0.0821 atm.L/Kmol
- Temperature = 295 K (i.e room temperature)
- Osmotic pressure (π) =?
π =iMRT
= 2 × 0.596 × 0.0821 × 295
= 29.3 atm