Final answer:
The 4.0 kg block exerts a force of 17 N on the 5.0 kg block and a force of 17 N on the 3.0 kg block due to the action-reaction principle described by Newton's third law.
Step-by-step explanation:
The scenario describes three blocks on a frictionless table with forces applied to them. To solve for the forces the blocks exert on each other, one can use Newton's second law and the concept of action-reaction pairs, according to Newton's third law.
Part A: Force Exerted by the 4.0 kg Block on the 5.0 kg Block
When a 17 N force is applied to the 3.0 kg block, the same force is transmitted through the 4.0 kg block to the 5.0 kg block because of Newton's third law. Since the table is frictionless, the force exerted on the 5.0 kg block is also 17 N.
Part B: Force Exerted by the 4.0 kg Block on the 3.0 kg Block
The 4.0 kg block exerts a force on the 3.0 kg block that is equal in magnitude and opposite in direction to the force the 3.0 kg block exerts on it. Hence, this force is also 17 N, by the action-reaction principle. Newton's third law states that for every action, there is an equal and opposite reaction. Here, the action is the force the 3.0 kg block exerts on the 4.0 kg block, and the reaction is the force that the 4.0 kg block exerts on the 3.0 kg block.