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A racecar travels northward on a straight, level track at a constant speed, traveling 0.550 kilometer in 40.0 seconds. The return trip over the same track is made in 45.0 seconds. (a) What is the average velocity of the car in meters per second for the first leg of the run? m/sec (b) What is the average speed for the total trip? (Round your answer to one decimal place.) m/sec

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Let's start by calculating the average velocity for the first leg of the journey.

(a) The average velocity can be calculated using the formula:

Average Velocity = Distance / Time

Firstly, convert the distance travelled from kilometers to meters for more precise calculation so 0.550 kilometers is equal to 550 meters (since 1 kilometer is equal to 1000 meters).

Given,
Distance = 550 meters
Time = 40 seconds

Substituting these values into the above formula, we get:

Average Velocity = 550 meters / 40 seconds = 13.75 m/sec

So, the average velocity for the first leg of the run is 13.75 m/sec.

Now, let's move on to the second part of the question.

(b) To get the average speed for the total trip, we simply use the formula:

Average Speed = Total Distance / Total Time

Again, convert the distance for the return leg from kilometers to meters. The total distance traveled is thus 2*550 = 1100 meters (550 meters for each leg) and the total time is 40 seconds + 45 seconds = 85 seconds.

Substituting these values into the formula gives us:

Average Speed = 1100 meters / 85 seconds ≈ 12.9 m/sec (rounded to one decimal place)

Hence, the average speed for the total trip is 12.9 m/sec.

User Kenneth Reitz
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