Question

A supermarket is holding a raffle for a new wrist watch. Out of the 500 tickets sold, David buys ticketsnumbered 5, 6, 7, and 8. What are the odds in favor of David's winning the raffle?O 1:500O 500:1O 1:124O124:1

Answer 1

`\text{odds in favour of David winning = }1\text{ : 124 (option C)}`

Step-by-step explanation:

Total tickets = 500

Tickets number bought by David = 5, 6, 7 and 8

Number of tickets bought by David = 4

Remaining ticket = 500 - Number of tickets bought by David

Remaining ticket = 500 - 4

Remaining ticket = 496

Odds in favour of an event = success for the event/ failures for the event

success for winning the raffle = Number of tickets bought by David = 4

failures for winning the raffle = Remaining ticket = 496

`\begin{gathered} \text{odds in favour of David winning = }(4)/(496) \\ \text{odds in favour of David winning = }(1)/(124) \\ \\ \text{odds in favour of David winning = }1\text{ : 124 (option C)} \end{gathered}`