Question

How many grams of FeSO4 (molar mass = 151.9 g/mol) are present in a 200.0 mL sample of a 0.250 M solution? Enter your answer with 3 significant figures and do not include the unit

Answer 1

7.60grams

Explanations:

The formula for calculating the molarity of a solution is expressed as;

`molarity=(mole)/(volume)`

Given the following parameters

molarity of solution = 0.250M

volume of sample = 200mL

Substitute to determine the mole of the solute

`\begin{gathered} mole\text{ of }FeSO_4=molarity* volume \\ mole\text{ of }FeSO_4=(0.250mol)/(L)*0.2L \\ mole\text{ of }FeSO_4=0.05moles \end{gathered}`

Determine the required mass of FesO4

`\begin{gathered} Mass\text{ of FeSO}_4=mole* molar\text{ mass} \\ Mass\text{ of FeSO}_4=0.05*151.9 \\ Mass\text{ of FeSO}_4=7.595grams \\ Mass\text{ of FeSO}_4=7.60grams \end{gathered}`

Hence the mass of FeSO4 is 7.60grams