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Please explain and show all steps for these problems. 1) The angle of elevation of the sun is decreasing at a rate of \( 1 \mathrm{rad} / \mathrm{hr} \). How fast is the shadow cast by a \( 400-\mathrm{ft} \) tall building changing when the angle of elev

User Psyrus
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Sure, let's solve this step by step.

We know that the rate of decrease of the angle of the sun's elevation, d_θ/d_t, is -1 rad/hr. We also know that the height of the building, H is 400 feet.

The length of shadow, L, and the angle of elevation, θ, follows the basic trigonometry rule, tan(θ) = H / L. From this, we can derive that L = H / tan(θ).

We'll now differentiate both sides of this equation with respect to t:
dL/dt = -H * (sec^2(θ)) * d_θ/d_t

Now, at the point in time we're interested, let's assume θ = 45 degrees or π / 4 radians. In trigonometry, we know that sec^2(45) = 2. So,
dL/dt = -H * 2 * d_θ/d_t.

We substitute the given values into this equation. We have H=400 feet, and d_θ/d_t = -1 rad/hr. So,
dL/dt = -400 * 2 * -1 = 800 feet/hour.

Therefore, at the moment when the angle of elevation is 45 degrees, the shadow of a 400-feet building lengthens at a rate of 800 feet per hour as the angle of elevation of the sun decreases at a rate of 1 radian per hour.

User Ingalcala
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