Answer:
Therefore, the standard form of the equation 3y = 20 - √(2x) is 9y^2 - 120y - 2x + 400 = 0.
Explanation:
To rewrite the equation 3y = 20 - √(2x) in standard form, we need to isolate the variable terms on one side and the constant terms on the other side.
Step 1: Move the constant term (20) to the left side by subtracting it from both sides of the equation:
3y - 20 = -√(2x)
Step 2: Square both sides of the equation to eliminate the square root:
(3y - 20)^2 = (-√(2x))^2
9y^2 - 120y + 400 = 2x
Step 3: Move the x term to the right side by subtracting 2x from both sides of the equation:
9y^2 - 120y - 2x + 400 = 0
Therefore, the standard form of the equation 3y = 20 - √(2x) is 9y^2 - 120y - 2x + 400 = 0.