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Based on the reaction below, if the concentration of D decreases by 0.015M, what will be the change in concentration for B? 5 A(aq)+5 B(aq)→5 C(aq)+5 D(aq)

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Final answer:

Given the reaction 5 A(aq) + 5 B(aq) → 5 C(aq) + 5 D(aq), if the concentration of D decreases by 0.015M, then the concentration of B should increase by 0.015M, due to the 1:1 molar relationship.

Step-by-step explanation:

The reaction 5 A(aq) + 5 B(aq) → 5 C(aq) + 5 D(aq) indicates that the molar ratio of reactants A and B to products C and D is 1:1. Therefore, the change in concentration for B should be equal to the change in concentration for D, but in the opposite direction because B is being used up in the reaction. In this instance, if the concentration of D decreases by 0.015M, there will be an increase in concentration of B by 0.015M. This is under the assumptions of constant temperature and volume and that the system is at equilibrium (Le Chatelier's principle).

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