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A Stone of 350 g is thrown vertically up with velocity of 15 m/s. Calculate:

(i) The potential energy at the maximum height;
(ii) The kinetic energy of the stone on reaching the ground.
(4)
(2)

1 Answer

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Final answer:

The potential energy at the maximum height is 38.90 J. The kinetic energy of the stone on reaching the ground is 37.13 J.


Step-by-step explanation:

(i) To calculate the potential energy at the maximum height, we can use the formula:

Potential Energy (PE) = mass (m) * gravitational acceleration (g) * height (h)

Given that the mass of the stone is 350 g (0.35 kg) and the height it reaches is the maximum height, we need to find the height first. To find the height, we can use the formula:

Final velocity (v) = Initial velocity (u) - gravitational acceleration (g) * time (t)

Since the stone is thrown vertically up, the final velocity at the maximum height is 0 m/s. The initial velocity is 15 m/s and gravitational acceleration is 9.8 m/s^2. We can rearrange the formula to solve for time:

0 = 15 - 9.8 * t

Solving for t, we get t = 1.53 s. Now we can plug this value of t into the formula for height:

Height (h) = Initial velocity (u) * time (t) - 0.5 * gravitational acceleration (g) * time (t)^2

Plugging in the values, we get h = 15 * 1.53 - 0.5 * 9.8 * (1.53)^2 = 11.54 m. Now we can calculate the potential energy:

PE = 0.35 * 9.8 * 11.54 = 38.90 J

(ii) To calculate the kinetic energy of the stone on reaching the ground, we can use the formula:

Kinetic Energy (KE) = 0.5 * mass (m) * velocity (v)^2

At the maximum height, the stone has zero velocity. So, the velocity on reaching the ground will be the same as the initial velocity, which is 15 m/s. Plugging in the values, we get:

KE = 0.5 * 0.35 * 15^2 = 37.13 J


Learn more about Potential and Kinetic Energy

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