Answer:
0.36
Explanation:
The general form of a wave equation is:
y=Acos(Bx+C)+D
where A is the amplitude, B is the angular frequency, C is the phase shift, and D is the vertical shift.
To find the amplitude of the given wave, you need to compare it with the general form and identify the value of A. You can do this by expanding the parentheses and rearranging the terms:
y=0.3(0.7+1.2cos(2−xπ))
y=0.21+0.36cos(2−xπ)
y=0.36cos(2−xπ)+0.21
=> A=0.36, so that is the amplitude of the wave.
The amplitude is the maximum displacement of the wave from its equilibrium position, which is given by the vertical shift D. In this case, D=0.21, so the equilibrium position is y=0.21.
Therefore, the wave oscillates between y=0.21+0.36=0.57 and y=0.21−0.36=−0.15.
So, the final answer is: the amplitude of the wave is 0.36.