201k views
3 votes
what is an equation of the line that passes through the point (-4,-6) and is parallel to the line 5x-2y=2

User Markstar
by
7.4k points

1 Answer

2 votes

Answer:

y = 5/2x + 4

Explanation:

Relationship between the slopes of parallel lines:

  • The slopes of parallel lines are equal to each other.
  • This means that once we find the slope of 5x - 2y = 2, we'll also have the slope of the other line.

Identifying the form of 5x - 2y = 2:

The equation 5x - 2y = 2 shows the standard form of a line, whose general equation is given by:

Ax + By = C, where:

  • A, B, and C are constants.

We can easily find the slope of 5x - 2y = 2 by converting it to the slope-intercept form of a line, whose general equation is given by:

y = mx + b, where:

  • m is the slope,
  • and b is the y-intercept.

Converting 5x - 2y = 2 to slope-intercept form and identifying the slope:

Thus, we isolate y in 5x - 2y = 2 to find the slope of this line and the other line:

(5x - 2y = 2) - 5x

(-2y = -5x + 2) / -2

y = 5/2x - 1

Therefore, 5/2 is the slope of 5x - 2y = 2 and the other line.

Finding the y-intercept (b) of the other line and writing the equation of the line (in slope-intercept form):

Now, we can find the y-intercept of the other line by substituting 5/2 for m and (-4, -6) for b in the general equation of the slope-intercept form:

-6 = 5/2(-4) + b

-6 = -20/2 + b

(-6 = -10 + b) + 10

4 = b

Thus, the y-intercept of the line is 4.

Therefore, y = 5/2x + 4 is the equation of the line that passes through (4, -6) and is parallel to the line 5x - 2y = 2.

User Sharone Lev
by
8.3k points