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22 votes
Write the equation of the line that passes through the points (8, -1) and (2, -5) inpoint-slope form.

User SanDash
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1 Answer

7 votes
7 votes

First, we find the slope using the given points and the formula below


m=(y_2-y_1)/(x_2-x_1)=(-5-(-1))/(2-8)=(-5+1)/(-6)=(-4)/(-6)=(2)/(3)

Then, we use the point-slope formula to find the equation


y-y_1=m(x-x_1)_{}

Let's replace the point (8, -1) and the slope 2/3.


\begin{gathered} y-(-1)=(2)/(3)(x-8) \\ y+1=(2)/(3)x-(16)/(3) \\ y=(2)/(3)x-(16)/(3)-1 \\ y=(2)/(3)x+(-16-3)/(3) \\ y=(2)/(3)x-(19)/(3) \end{gathered}

Hence, the equation in point-slope form is


y+1=(2)/(3)(x-8)

User Pmg
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