Answer: 23.8°F
Explanation:
To find the logarithmic regression equation for wind speed and wind chill factor when the air temperature is 24°F, we can use the formula:
y = m*log(x) + b
where y is the wind chill factor, x is the wind speed in mph, m is the slope of the line, log(x) is the logarithm of x, and b is the intercept.
First, we need to find the slope and intercept of the line. We can do this by using some pairs of x and y values from the table. For example, if we use the points (1, 23) and (3, 9), we can find the slope and intercept using the formulas:
m = (y2 - y1)/(x2 - x1)
b = y1 - m*x1
Plugging in the values, we get:
m = (9 - 23)/(3 - 1) = -14/2 = -7
b = 4 - (-7) * 3 = 23 - 21 = 2
So the logarithmic regression equation for wind speed and wind chill factor when the air temperature is 24°F is:
y = -7*log(x) + 2
To find the wind chill factor when the wind speed is 20 miles per hour, we can substitute 20 for x in the equation:
y = -7*log(20) + 2
y = 23.8
So the wind chill factor when the wind speed is 20 miles per hour is approximately 23.8°F.