Question

a particular inductive circuit produces 6kw of true power while producing 4kvar of reactive power. calculate: the apparent power the power facotr

Answer 1

The apparent power in the circuit is 7.21 kVA and the power factor is 0.831.

The apparent power in an inductive circuit can be calculated using the formula:

`S = √(P^2 + Q^2)`

where S is the apparent power, P is the true power, and Q is the reactive power.

In this case, the true power is 6 kW and the reactive power is 4 kVAR. Substituting these values into the formula,

`S = √(6^2 + 4^2) = √(36 + 16) = √52 = 7.21 kVA.`

The power factor can be calculated using the formula:

Power factor = P / S

Substituting the given values,

Power factor = 6 kW / 7.21 kVA = 0.831.