Final answer:
The energy released per gram of propane when it is burned is -2220 kJ/mol.
Step-by-step explanation:
To calculate the energy released per gram of propane when it is burned in a combustion reaction, we need to consider the balanced chemical equation for the combustion of propane and the enthalpy of combustion. The balanced chemical equation is C3H8 + 5O2 → 3CO2 + 4H2O, and the enthalpy of combustion for propane is -2220 kJ/mol. To find the energy released per gram of propane, we first need to find the molar mass of propane, which is 44.1 g/mol (12.01 g/mol * 3 + 1.01 g/mol * 8). Now we can calculate the energy released per gram of propane using the equation:
Energy released per gram = (Enthalpy of combustion * Molar mass of propane) / 44.1 g/mol
Substituting the values:
Energy released per gram = (-2220 kJ/mol * 44.1 g/mol) / 44.1 g/mol = -2220 kJ/mol
Therefore, the energy released per gram of propane when it is burned is -2220 kJ/mol.
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