Question

The amount of salt in solution A is 4×10^12 grams in the amount of salt in solution B is 8×10^10 grams how many times greater is the amount of salt and solution A the amount of salt in solution B

Answer 1

Explaination:
To divide these values, we can write it as a fraction: (4×10^12 grams) / (8×10^10 grams).

Next, let's simplify the fraction. We can cancel out a common factor of 4 between the numerator and denominator:

(4×10^12 grams) / (8×10^10 grams) =
(1×10^12 grams) / (2×10^10 grams).

Now, we can simplify further by dividing the numerator and denominator by 10^10:
(1×10^12 grams) / (2×10^10 grams) = (1/2) ×
(10^12 / 10^10) = (1/2) × 10^12-10) = (1/2) x
10^2.

Finally, we can simplify the expression:
(1/2) × 10^2 = 1/2 × 100 = 50.

Therefore, the amount of salt in solution A is 50 times greater than the amount of salt in solution B.

Answer 2

50 times greater

Explanation:

In order t find how many times greater the amount of salt in solution A is than the amount of salt in solution B, we can divide the amount of salt in solution A by the amount of salt in solution B.

`\sf (4 * 10^(12) grams)/(8 * 10^(10) grams) = 50`

Therefore, the amount of salt in solution A is 50 times greater than the amount of salt in solution B.