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The RC charging circuit in a camera flash unit has a voltage source of 285 V and a capacitance of 116 µF. A. Find its resistance R (in ohms) if the capacitor charges to 90.0% of its final value in 14.2 s.

User Darckeen
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The camera flash unit is essentially an RC charging circuit. To solve for the resistance, we first need to understand that in an RC circuit, when a capacitor charges to a certain percentage of its final value, this can be described by the equation:

t = -RC * ln(1 - percentage)

where:
- t is the charging time,
- R is the resistance,
- C is the capacitance, and
- ln is the natural logarithm.

Here, we're given that the capacitance is 116 µF (but we must convert it to farads by multiplying by 10^-6), the charging time is 14.2 seconds, and the capacitor charges to 90.0% of its final value (expressed as 0.9 in our formula).

We're asked to find the resistance, R. We begin by rearranging the formula to isolate R:

R = -t / (C * ln(1 - percentage))

Substituting the given values:

R = -14.2 / ((116 * 10^-6) * ln(1 - 0.9))

After making this calculation, we find that the resistance, R, is approximately 53163.635 Ω.

So, the resistance of the RC charging circuit is approximately 53.1 kΩ.

User Goncalossilva
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