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Given: CMʰᵃʳʳ is a perpendicular bisector of vec (AB) at point M. Prove: AC=BC

User Demonedge
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Firstly, we are given that CM is a perpendicular bisector of segment AB at point M. This means that CM is a line that splits AB into two equal segments at a 90 degree angle. Therefore, point M is the midpoint of line segment AB.

In vector terms, we can describe our points as follows:

A(0,0) represents the initial point of our vectors.

B(b1,b2) represents the terminal point of our vectors.

Since M is the midpoint of AB, we will have AM = MB.

In vectors, the midpoint Formula is M = (A+B)/2

Substituting the coordinates of A and B into the midpoint formula:

M = ([0, 0] +[b1, b2])/2 = [b1/2, b2/2]

This result shows that the point M(b1/2, b2/2) is the midpoint of AB which confirms that AM = MB.

Given that CM is a perpendicular bisector of AB, it implies that AC = BC. This is because a perpendicular bisector of a segment is a line which cuts the segment into two equal parts at 90 degrees.

Therefore, AC = BC = Length of AM = Length of MB.

Thus, the lengths of segments AC and BC are equal.

User Walkiria
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