Answer:
when t = 27, the acceleration of the car is 4
Explanation:
To find the acceleration of the car when t = 27, we need to differentiate the function f(t) = t^(4/3) with respect to t.
Differentiating f(t) = t^(4/3) involves using the power rule of differentiation, where the derivative of t^n with respect to t is given by n*t^(n-1).
Applying the power rule, we get:
f'(t) = (4/3)*t^(4/3 - 1)
Simplifying the exponent, we have:
f'(t) = (4/3)*t^(1/3)
Now, let's substitute t = 27 into the expression for f'(t) to find the acceleration:
f'(27) = (4/3)*(27)^(1/3)
Evaluating the exponent, we get:
f'(27) = (4/3)*(3)
Simplifying the fraction, we have:
f'(27) = 4
Therefore, when t = 27, the acceleration of the car is 4.
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