Question

Write a quadratic function in standard form with zeros 6 and 8

Answer 1

f(x) = x^2 - 14x + 48

Explanation:

Okay, here is a quadratic function in standard form with zeros (roots) of 6 and 8:

f(x) = (x - 6)(x - 8)

To get a quadratic function in standard form (ax^2 + bx + c) with given zeros, we take the product of the linear factors (x - r1)(x - r2) where r1 and r2 are the zeros.

Then we expand this product:

(x - 6)(x - 8)

= x^2 - 14x + 48

Therefore, the quadratic function in standard form with zeros of 6 and 8 is:

f(x) = x^2 - 14x + 48

The standard form uniquely determines the quadratic formula based on the zeros (roots) of the function.