Question

b. Calculate the electric force that exists between two objects that are 0.500 m apart and carrycharges of 0.00450 C and 0.00240

Answer 1

Given

The two charges,

`\begin{gathered} q_1=0.00450\text{ C} \\ q_2=0.00240\text{ C} \end{gathered}`

Distance between them,

`r=0.5\text{ m}`

To find

The electric force

Step-by-step explanation

We know the force is given by

`F=(kq_1q_2)/(r^2)`

Putting the values,

`\begin{gathered} F=9*10^9(0.00450*0.00240)/((0.500)^2) \\ \Rightarrow F=388,800\text{ N} \end{gathered}`

Conclusion

The electric force is 388,800 N