Question

Example 11

Two metals A and B lose the same quantity of heat when their temperatures drop
from 20°C to 15°C. If the specific heat capacity of A is thrice that of B, calculate the ratio
of the mass of A to that of B.
NECO 2005
Solution

Answer 1

The ratio of the mass of metal A to metal B is 1:3.

Step-by-step explanation:

To calculate the ratio of the mass of A to B, we can use the equation Q = mcΔT, where Q is the heat lost, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Since A and B lose the same quantity of heat, we can set up the equation as:

mcΔT = mcΔT
3mc(20 - 15) = mc(20 - 15)
3(5m) = 5m
15m = 5m
Rearranging the equation, we find that the ratio of the mass of A to B is 5:15 or 1:3.

Learn more about specific heat capacity