Question

Which is the correct solution of x2+7x+12=0? Question 7Select one: -6 and-2 -6 and-1 -4 and-3 -5 and-2

Answer 1

>>> -4 and -3

Explanation:

Given Equation :

• x² + 7x + 12 = 0

We have to Find :

• Solution of the given equation

Solution :

For finding the solution or we can say value of x of the given Equation , We are solving this equation by using middle term splitting method.

`\longmapsto \: \: \: \sf{x {}^(2) + \bold{7x} + 12 = 0 }`

Step 1 : Splitting the middle term that is 7x into 3x and 4x :

`\longmapsto \: \: \: \sf{x {}^(2) + \bold{3x + 4x} + 12 = 0 }`

Step 2 : Now taking x common from ( x² + 3x ) and taking 4 common from ( 4x + 12 ) :

`\longmapsto \: \: \: \sf{x(x + 3) + 4(x + 3)= 0 }`

We get ,

`\longmapsto \: \: \: \sf{(x + 3) (x + 4)= 0 }`

Step 3 : For finding Value of x , We have to equate ( x + 3 ) and ( x + 4 ) with 0 :

`\dashrightarrow \: \: \: \sf{x + 3 = 0}`

Subtracting both sides with 3 :

`\dashrightarrow \: \: \: \sf{x + \cancel{3 }- \cancel{3}= - 3}`

`\dashrightarrow \: \: \: \underline{ \boxed{ \sf{ \bold{ \blue{x = - 3}}}}} \: \: \: \bigstar`

and ,

`\dashrightarrow \: \: \: \sf{x + 4 = 0}`

Subtracting both sides with 4 :

`\dashrightarrow \: \: \: \sf{x + \cancel{4 }- \cancel{4 }= 0 - 4}`

We get ,

`\dashrightarrow \: \: \: \underline{ \boxed{ \sf{ \bold{ \blue{x = - 4}}}}} \: \: \: \bigstar`

• Therefore , solution of given Equation are " -4 and -3 "

Hope, it'll help you!!