Question

the position of an object is given by: x(t)=2t^3-35t^2+10 what is the acceleration of the object at t=250 seconds?

Answer 1

We are given that a particle's position is determined by the function:

`x\left(t\right)=2t^3-35t^2+10`

We are asked to determine the acceleration of the object. To do that we will first determine the first derivative of the position with respect to time, i. e. the velocity of the particle:

`(dx)/(dt)=(d)/(dt)(2t^3-35t^2+10)`

Now, we distribute the derivative operator:

`(dx)/(dt)=(d)/(dt)(2t^3)-(d)/(dt)(35t^2)+(d)/(dt)(10)`

Now, we use the following rule to determine each derivative: