Answer:
2x^2 -2x +16 = 0
Explanation:
Standard form for a quadratic equation is ...
ax^2 +bx +c = 0
You have an x-term on the right side of the equal sign, so you want to subtract that from both sides:
2x^2 -x +16 -x = x -x
2x^2 -2x +16 = 0
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Additional comment
The equation will remain in standard form, and will have the same properties (roots, vertex, line of symmetry, and so on) if we divide both sides by the greatest common factor of the coefficients, 2. (Standard form of a linear equation requires the coefficients be mutually prime, and the leading coefficient be positive. That is what this accomplishes for this quadratic. AFAIK, there is no requirement placed on general polynomial "standard form" that requires the coefficients be mutually prime.) Standard form does require the terms be listed in order of decreasing degree.
x^2 -x +8 = 0 . . . . equivalent to the given quadratic