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A sledge of mass 15 kg is being pulled up a slope which makes an angle of 10° to the horizontal. The sledge is being pulled by a rope which makes an angle of 20° to the slope. The sledge starts at rest and after travelling 10 m it has a speed of 2 ms⁻¹. Assuming resistance forces can be ignored, the tension in the rope is

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The tension on the rope is 3. 19N

The net force along the slope is related to the acceleration, that is,

F net = ma

Substitute the value of the mass

F net = 15kg ×a

Given that the sledge starts from rest and attains a speed of 2m/s after traveling 10m, we can use the equations of motion to find the acceleration.

v²= u² + 2as

substitute the values

2² = 0 + 2 ×a × 10

multiply the values

a = 4/20

a = 0. 2m/s²

Now, the net force along the slope is;

F net = 15 kg × 0.2m/s² = 3N

This net force along the slope is the force parallel to the slope.

F. parallel = T cos 20 = 3N

Then, we have;

T = 3/cos 20

T = 3. 19N

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