Question

X²+13+42
X²-7x+12
X²+3x-10
X²-4x-21
X²+3x+2

Answer 1

Explanation:

I guess you want to factor these.

x^2+13x+42

We need 2 numbers whose product is +42 and whose sum is +13.

These are + 6 and + 7 so we have the factors;

= (x + 6)(x + 7).

X^2-7x+12

+12 = -4 * -3 and -4-3 = -7 so we have:

(x - 3)(x - 4).

X²+3x-10

-10 = +5 * -2 and +3 = 5 - 2

So it is

(x + 5)(x - 2)

The rest are done in the same way:

X²-4x-21

= (x - 7)(x + 3)

X²+3x+2

= (x + 1)(x + 2).