we have
f(x) = |x – 1] + 2
g(x) = -2f(x) + 8
substitute the value of f(x) in g(x)
so
g(x)=2(|x – 1] + 2) +8
g(x)=2|x – 1] + 4 +8
g(x)=2|x – 1] + 12
Using a graphing tool
see the attached image
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