Final answer:
The resistance that must be added in parallel to a 10 Ohm resistor to result in a total resistance of 2 Ohms is 10/3 Ohms, which is not given in the options. This is calculated using the formula for resistors in parallel.
Step-by-step explanation:
The subject of this question revolves around the concept of resistors in parallel in a circuit, which falls under the domain of physics. To find the resistance that, when placed in parallel with a 10Ohm resistor, will result in a combined resistance of 2 Ohms, we can use the formula for parallel resistance: 1/Req = 1/R1 + 1/R2.
In this case, R1 = 10Ohm is known, and Req = 2Ohm is the total resistance we want after adding another resistor in parallel. Plugging these values into the equation, we can solve for R2, which is the resistance of the resistor that needs to be added to get the total resistance as 2 Ohms.
From the calculation 1/R2 = 1/Req - 1/R1 = 1/2 - 1/10 = 3/10.Therefore the solution is R2 = 10/3 Ohm.
None of the options A.5 Ohms B.1Ohm C.2.5Ohm D.1.25Ohm are correct. The correct answer should be 10/3 Ohms
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