Question

the quarterback throws the football, but this time the model y = –16x² + 35x + 6.5 describes the height (y), in feet, of the football x seconds after it is thrown. if the ball is not caught, how long will it be in the air? 0 = –16x² + 35x + 6.5 x = -35 ± √35² - 4(-16)(6.5) / 2(-16) Rounded to the nearest tenth, the solutionas of the equation are ? A. -2.4 , 0.2 B. -0.2 , 0.9 C. 0.2 , 2.4

Answer 1

The ball will be in the air for approximately 0.2 seconds.

Step-by-step explanation:

The given equation y = -16x² + 35x + 6.5 represents the height of the football in feet (y) at x seconds after it is thrown. To find out how long the ball will be in the air, we need to solve the equation when y = 0. By substituting y = 0 into the equation, we get:

0 = -16x² + 35x + 6.5

Using the quadratic formula, we have:

x = (-35 ± √(35² - 4(-16)(6.5))) / (2(-16))

Rounded to the nearest tenth, the solutions are x = -2.4 and x = 0.2. Since time cannot be negative, the ball will be in the air for approximately 0.2 seconds.

Answer 2

The answer is C. 0.2 , 2.4; it is correct on Edge.