Question

C*(UPQuestion 6 of 26šiWhich of the following sets of quantum numbers is not allowed?A) n = 1, l = 0, ml = 0B) n = 4, f = 0, ml = -1C) n = 3, l = 1, ml = 0D) n = 2,1 = 0, ml = 0E) n = 3, l = 2, ml = -2

Answer 1

Let's analyze option B:

Given that n=4, l=0 and ml=-1, we could draw:

If we have n=4, l=0, that means that the electron configuration ends at 4s. As you can notice, "s" orbital can only adquire one pair of electrons and ml can only be 0. In the answer option this is -1, so this option is not correct.

The answer is B.