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19 votes
19 votes
What is the remainder when j(x)=x4+2x3−5x2+2x+4 is divided by x+3

What is the remainder when j(x)=x4+2x3−5x2+2x+4 is divided by x+3-example-1
User Callo
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2.9k points

1 Answer

10 votes
10 votes

From the problem, we have a function :


j(x)=x^4+2x^3-5x^2+2x+4

The remainder when j(x) is divided by x + 3 is the value of the function when x = -3

x = -3 comes from :

x + 3 = 0

x = -3

Substitute x = -3 to the function,


\begin{gathered} j(-3)=(-3)^4+2(-3)^3-5(-3)^2+2(-3)+4 \\ j(-3)=81-54-45-6+4 \\ j(-3)=-20 \end{gathered}

The answer is -20

User Mukarram Ishaq
by
2.5k points
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