Question

A toy rocket starts from rest on the ground and then accelerates at 39.2 m/s^2 for 5 seconds. A) The final velocity of the rocket is 196 m/s. B) The rocket travels a distance of 490 meters. C) The initial velocity of the rocket is 0 m/s. D) The rocket reaches a maximum height of 490 meters.

Answer 1

The Physics problem at the high school level involves calculating the final velocity, distance traveled, initial velocity, and maximum height of a toy rocket using kinematic equations.

Step-by-step explanation:

The subject of the given question is Physics, as it deals with concepts such as acceleration, velocity, distance, and height pertaining to the motion of a toy rocket. These are all typical physics topics covered in high school curriculums. The student's task involves applying the kinematic equations of motion to solve for various parameters of the rocket's flight.

The correct answers to the student's question, based on the provided acceleration and duration of the acceleration, are:
A) Final velocity of the rocket is indeed 196 m/s.
B) The total distance traveled by the rocket is incorrectly stated as 490 meters, and this can be calculated using the equation for distance under constant acceleration (d = v0t + (1/2)at2).
C) The initial velocity of the rocket is accurately stated to be 0 m/s as it starts from rest.
D) The maximum height reached by the rocket cannot be determined with the given information alone and would require knowing the entire flight duration or conditions at apogee.

Answer 2

This Physics question, appropriate for High School level, involves calculating a toy rocket's final velocity, distance traveled, and initial velocity based on its acceleration, which can be found using kinematic equations.

Step-by-step explanation:

The subject of this question is Physics, and it pertains to the concepts of mechanics, specifically kinematics and dynamics as they relate to the motion of a toy rocket under constant acceleration. The question falls within the High School grade level due to the use of basic kinematic equations.

The question asks about a toy rocket that accelerates from rest at a rate of 39.2 m/s2 for 5 seconds. We can use the kinematic equation v = u + at to determine the final velocity, where v is the final velocity, u is the initial velocity (which is 0 m/s), a is the acceleration, and t is the time. The distance covered by the rocket can also be calculated using the equation s = ut + (1/2)at2.

Here are the calculations:

• Final velocity: v = 0 + (39.2 m/s2)(5 s) = 196 m/s
• Distance traveled: s = (0)(5 s) + (1/2)(39.2 m/s2)(5 s)2 = 490 m
• Initial velocity: u = 0 m/s, as stated in the problem
• Maximum height: If the rocket were to stop at the peak (in the absence of any other forces), the height it reaches would also be the distance traveled, which is 490 m, although this would not hold if gravity were taken into account