Question

Consider the following rational expression:2 – 2y / 2y - 2Step 1 of 2: Reduce the rational expression to its lowest terms.Answer

Answer 1

`\begin{gathered} \text{Given} \\ (2-2y)/(2y-2) \end{gathered}`

Factor out 2 on both numerator and denominator

`\begin{gathered} (2-2y)/(2y-2) \\ =(2(1-y))/(2(y-1)) \\ \\ \text{cancel out }2\text{ on both numerator and denominator} \\ =\frac{\cancel{2}(1-y)}{\cancel{2}(y-1)} \\ =((1-y))/((y-1)) \\ \\ \text{factor out }-1\text{ on numerator},\text{ and rearrange to cancel out common binomial} \\ =((1-y))/((y-1)) \\ =(-1(-1+y))/((y-1)) \\ =(-1(y-1))/((y-1)) \\ =\frac{-1\cancel{(y-1)}}{\cancel{(y-1)}} \\ =-1 \\ \\ \text{Therefore,} \\ (2-2y)/(2y-2)=-1 \end{gathered}`

Part 2:

Since the given expression is in fraction, we cannot let the denominator equal to zero. Find values of y that makes the denominator by zero

`\begin{gathered} \text{Denominator: }2y-2 \\ \\ \text{Equate to zero} \\ 2y-2=0 \\ 2y-2+2=0+2 \\ 2y\cancel{-2+2}=2 \\ (2y)/(2)=(2)/(2) \\ y=1 \\ \\ \text{If }y=1,\text{ the denominator }2y-2\text{ becomes zero therefore}, \\ y\\eq1 \end{gathered}`