Answer:
Step-by-step explanation:
The force on a charged particle moving in a magnetic field can be calculated using the formula:
F = qvBsinθ
where
F is the force on the particle
q is the charge of the particle
v is the velocity of the particle
B is the magnetic field strength
θ is the angle between the velocity and magnetic field vectors.
In this case, the charge on the particle is +3.0x10^-6C, its velocity is 300,000m/s, and the magnetic field is 1.4T. The angle between the velocity and magnetic field vectors is 90° because the particle is moving perpendicular to the magnetic field.
So, plugging in the values to the formula, we get:
F = (3.0x10^-6C)(300,000m/s)(1.4T)sin90°
F = (3.0x10^-6C)(300,000m/s)(1.4T)(1)
F = 1.26x10^-2 N
Therefore, the force on the particle is 1.26x10^-2 N to the left of the page, perpendicular to the velocity of the particle.