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what is the surface area of a cylinder with a height of 5 feet and base radius of 8 feet round to the nearest hundredth
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4 votes
what is the surface area of a cylinder with a height of 5 feet and base radius of 8 feet round to the nearest hundredth

User Abela
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2 Answers

4 votes
The surface area would be 653.45
User Olleg
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6.5k points
7 votes

Answer:

The answer is 653.45 ft

Explanation:

A=2πrh+2πr2=2·π·8·5+2·π·82≈653.45127ft²

User JEL
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7.6k points
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