Question

2. Now rewrite the code to traverse the array in column major order. Write the output (write the numbers across to the right) on the line below, and write the code in the box below the line.

public class Test
{
public static void main(String[] args)
{
int[][] array = {{1,2,3},{4,5,6}};
for (int row = 0; row < array.length; row++)
{
for (int col = 0; col < array[0].length; col++)
{
System.out.println( array[row][col] );
}
}
}
}

Answer 1

The given code traverses the 2D array in row major order. The task is to rewrite the code to traverse the array in column major order.

To traverse the array in column major order, we need to change the order of loops. The outer loop should traverse the column and the inner loop should traverse the rows.

The output will be written in a single line across to the right.

The modified code to traverse the array in column major order is:

```

public class Test{

public static void main(String[] args)

{

int[][] array = {{1,2,3},{4,5,6}};

for (int col = 0; col < array[0].length; col++)

{

for (int row = 0; row < array.length; row++)

{

System.out.print( array[row][col] + " ");

}

System.out.println();

}

}

}

```

The output of the above code will be:

`1 4`

`2 5`

`3 6`