Answer:
The correct answer is: There is a 25% chance the baby will have Type A blood, a 25% chance the baby will have Type B blood, and a 50% chance the baby will have Type O blood.
To determine the possible blood types of the baby, we need to use the Punnett square method.
First, we need to determine the possible alleles that the parents can pass on to their offspring. The father has the genotype I Ai, which means he can pass on either the A allele or the i allele to his offspring. The mother has the genotype I Bi, which means she can pass on either the B allele or the i allele to her offspring.
We can represent the possible alleles that each parent can pass on using a Punnett square:
| A i
---|-------
I B| AB Bi
i | Ai ii
From the Punnett square, we can see that there are four possible genotypes for the baby: IAIB (Type AB), IAi (Type A), IBi (Type B), and ii (Type O).
The probability of each genotype is as follows:
IAIB (Type AB): 1/4 or 25%
IAi (Type A): 1/4 or 25%
IBi (Type B): 1/4 or 25%
ii (Type O): 1/4 or 25%
Since the A and B alleles are codominant, if the baby inherits both the A and B alleles (IAIB genotype), then the baby will have Type AB blood. If the baby inherits only the A allele (IAi genotype) or only the B allele (IBi genotype), then the baby will have Type A or Type B blood, respectively. If the baby inherits two copies of the i allele (ii genotype), then the baby will have Type O blood.
Therefore, the correct answer is: There is a 25% chance the baby will have Type A blood, a 25% chance the baby will have Type B blood, and a 50% chance the baby will have Type O blood.