Answer:To calculate the number of grams of Lysol required to make a 3% solution of 1200 mL, we need to know the density of Lysol and its percentage concentration in the solution.
Unfortunately, the percentage concentration of Lysol is not specified, as there are many different types of Lysol products with varying concentrations of active ingredients. For example, Lysol All-Purpose Cleaner contains 0.1% alkyl (C12-18) dimethyl benzyl ammonium chloride, while Lysol Disinfectant Spray contains 0.1% benzalkonium chloride.
Assuming we have a Lysol product that contains 100% Lysol as its active ingredient and a density of 1 g/mL, we can calculate the amount of Lysol required as follows:
3% of 1200 mL = 0.03 x 1200 mL = 36 mL
Since the density of Lysol is 1 g/mL, 36 mL of Lysol is equal to 36 grams of Lysol.
Therefore, if we assume the Lysol product used is 100% Lysol and has a density of 1 g/mL, we would need 36 grams of Lysol to make a 3% solution of 1200 mL.
Explanation: