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Determine the equation of the circle with center (9, —8) containing the point (1,7).

User Semmel
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1 Answer

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Answer:

(x - 9)^2 + (y + 8)^2 = 17^2

Step by step solved:

The equation of a circle with center (a,b) and radius r is given by:

(x - a)^2 + (y - b)^2 = r^2

We are given the center of the circle as (9, -8), and we know that it contains the point (1,7). Let's call the radius of the circle r.

Substituting the given values into the equation, we get:

(1 - 9)^2 + (7 - (-8))^2 = r^2

(-8)^2 + (15)^2 = r^2

64 + 225 = r^2

289 = r^2

r = √289

r = 17

Therefore, the equation of the circle is:

(x - 9)^2 + (y + 8)^2 = 17^2
User Vitperov
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