Answer:
The pressure of the gas sample at a volume of 0.4250 L is 551.8 mmHg.
Step-by-step explanation:
We can use the combined gas law to solve this problem:
P1V1/T1 = P2V2/T2
P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature.
We can rearrange this equation to solve for P2:
P2 = (P1 x V1 x T2) / (V2 x T1)
We are given:
P1 = 93.5 mmHg
V1 = 2.50 L
V2 = 0.4250 L
T1 and T2 are assumed to be constant (not given)
Substituting these values into the equation, we get:
P2 = (93.5 mmHg x 2.50 L x T2) / (0.4250 L x T1)
Simplifying, we get:
P2 = 551.8 mmHg
The pressure of the gas sample at a volume of 0.4250 L is 551.8 mmHg.