Answer:
Each XY molecule is formed from two X atoms and one Y2 molecule. The bond energy of X-Y is not given in the problem statement, so we cannot calculate it directly. However, we can use the bond energies of the other bonds to estimate it using Hess's law.
According to Hess's law, the total energy change for a reaction is the same whether it occurs in one step or in a series of steps.
We can therefore use the bond energies of the other bonds to estimate the bond energy of X-Y as follows:
The bond energy of X-X is 171 kJ/mol (from a table of bond energies).
The bond energy of Y-Y is 418 kJ/mol (also from a table of bond energies).
To estimate the bond energy of X-Y, we can use the following reaction: X + Y2 → XY + Y (this is the reverse of the reaction we are interested in). The bond energy of Y-Y cancels out, and we are left with:
X + Y2 → XY + Y
(2 X-Y) + (1 Y-Y) - (2 X-X) = ΔH
2 (X-Y) - 1 (Y-Y) - 2 (X-X) = ΔH
2 (X-Y) - 2 (X-X) = ΔH
2 (X-Y) = ΔH + 2 (X-X)
(X-Y) = ΔH/2 + (X-X)
We know that the total bond energy of the products (2XY) is 1256 kJ/mol, so the bond energy of one XY molecule is 628 kJ/mol (1256 kJ/mol divided by 2).
Using the equation we derived above, we can calculate the bond energy of X-Y as follows:
(X-Y) = ΔH/2 + (X-X)
(X-Y) = (628 kJ/mol)/2 + 171 kJ/mol
(X-Y) = 314 kJ/mol + 171 kJ/mol
(X-Y) = 485 kJ/mol
The total bond energy of the products (2XY) is therefore 2 x 485 kJ/mol = 970 kJ/mol.
The difference between the total bond energy of the reactants (732 kJ/mol) and the total bond energy of the products (970 kJ/mol) is:
ΔH = total bond energy of products - total bond energy of reactants
= 970 kJ/mol - 732 kJ/mol
= 238 kJ/mol