Question

What is the equation of a line, in point-slope form, that passes through (-8, 1) and has a slope of 5/6?​

It's not necessary but I would appreciate an explanation so I can learn it as well!!!

Answer 1

B. y - 1 = 5/6(x + 8)

Explanation:

Point-slope form: y - y1 = m(x - x1)

we have slope m = 5/6, y1 = 1 and x1 = -8

(x1,y1) is the point the line passes through

therefore

y - 1 = 5/6(x - -8)

y - 1 = 5/6(x + 8)

Answer 2

The point-slope form of the equation of a line is: y - y1 = m(x - x1), where m is the slope of the line and (x1, y1) is a point on the line.

We are given the point (-8, 1) and the slope 5/6. So, we can substitute these values into the point-slope form equation and simplify:

y - y1 = m(x - x1)

y - 1 = (5/6)(x - (-8))

y - 1 = (5/6)(x + 8)

y - 1 = (5/6)x + (5/6)(8)

y - 1 = (5/6)x + 20/3

Therefore, the equation of the line, in point-slope form, that passes through (-8, 1) and has a slope of 5/6 is:

y - 1 = (5/6)x + 20/3