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When a living organism dies, its carbon-14 decays. The half life of carbon-14 is

5730 years. If the skeleton of a human is discovered and has 20% of its original
carbon-14 remaining, how long ago did the human die?

User Razorphyn
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1 Answer

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Answer: The amount of carbon-14 remaining after a certain amount of time can be modeled by the exponential decay function:

N(t) = N0 * e^(-kt)

where N0 is the initial amount of carbon-14, k is the decay constant, and t is the time elapsed since the death of the organism.

We know that the half-life of carbon-14 is 5730 years. This means that the amount of carbon-14 remaining after one half-life is:

N(5730) = 0.5N0

Solving for the decay constant k, we get:

0.5N0 = N0 * e^(-k * 5730)

0.5 = e^(-k * 5730)

ln(0.5) = -k * 5730

k = ln(2) / 5730

Now, we can use the fact that the skeleton has 20% of its original carbon-14 remaining to solve for the time since death. Let T be the time elapsed since death. Then, we have:

N(T) = 0.2N0 = N0 * e^(-k * T)

Solving for T, we get:

T = -ln(0.2) / k

Plugging in the value of k, we get:

T = -ln(0.2) / (ln(2) / 5730) ≈ 17089 years

Therefore, the human died approximately 17089 years ago.

Explanation:

User Sogartar
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