Answer: B4
(Not including the beginning Figure 24.5 is the wave traveling? Section 24.2 4.)
Step-by-step explanation:
If you yell in front of a tall rock wall that is 170 meters away, it will take approximately 1 second for the echo to get back to your ears. This is because the sound has to travel the distance to the wall and back, so the total distance traveled by the sound is 340 meters (170 meters to the wall and 170 meters back), and sound travels at a speed of 340 m/s, so the time it takes is:
Time = Distance/Speed = 340 meters / 340 m/s = 1 second
The frequency of the sound wave can be calculated using the formula:
frequency = speed/wavelength
So, the frequency of the sound wave with speed 340 m/s and wavelength 10 meters is:
frequency = 340 m/s / 10 meters = 34 Hz
This is a very low frequency sound, which is below the range of human hearing.
The longest wavelength that can be heard by humans is when the frequency is 20 Hz, using the formula:
wavelength = speed/frequency = 340 m/s / 20 Hz = 17 meters
The shortest wavelength that can be heard by humans is when the frequency is 20,000 Hz, using the same formula:
wavelength = speed/frequency = 340 m/s / 20,000 Hz = 0.017 meters or 1.7 centimeters
To find the frequency of the E note one octave higher, we need to double the frequency of the original note. Doubling the frequency is equivalent to increasing it by one octave. Therefore, the frequency of the E note one octave higher is:
330 Hz x 2 = 660 Hz
To find the frequency of the note one octave lower than a frequency of 988 Hz, we need to halve the frequency. Halving the frequency is equivalent to decreasing it by one octave. Therefore, the frequency of the note one octave lower is:
988 Hz / 2 = 494 Hz
This note is B4.