Answer:
0.1331 J
Step by step explanation:
The work required to stretch a spring is given by the formula:
W = (1/2)kx^2
where W is the work done, k is the spring constant, and x is the displacement from the equilibrium position.
The initial displacement of the spring is 0.23 m, and the final displacement is 0.23 m + 0.11 m = 0.34 m. Therefore, the displacement of the spring is Δx = 0.34 m - 0.23 m = 0.11 m.
The work required to stretch the spring an additional 0.11 m is:
W = (1/2)k(Δx)^2
= (1/2)(22 N/m)(0.11 m)^2
= 0.1331 J
Therefore, the work required to stretch the spring an additional 0.11 m is 0.1331 J.